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Program for Armstrong Number Between Two Intervals in Python

Wondering how to find armstrong number between two intervals in Python? Well, you have landed on the right tutorial here. We are going to see practical examples of it, whether you want to find armstrong numbers between 1 to 10000 in Python or check the armstrong numbers in a given range. 

These programs are very useful for mathematics enthusiasts, Python programmers and developers, as well as aspiring tech geeks. Learning to find Armstrong numbers in an interval using Python opens up a multitude of exciting possibilities for honing your skills and unraveling the mysteries of number theory.

An Armstrong number, also known as a narcissistic number, is a special kind of number where the sum of its individual digits raised to the power of the number of digits equals the original number itself. 

For instance, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 equals 153.

The ability to find Armstrong numbers within a range has practical applications in various fields. For example, in the domain of data validation or error-checking mechanisms, identifying Armstrong numbers can be used to ensure data integrity and accuracy during data transmission or storage.

Additionally, Armstrong numbers serve as a fascinating gateway to delve deeper into mathematical concepts such as digit manipulation, modular arithmetic, and mathematical patterns. By honing your skills in identifying Armstrong numbers, you develop a stronger foundation for tackling more advanced mathematical problems and exploring related areas, including cryptography, algorithmic problem-solving, and data analysis.

By leveraging Python's versatility, we can efficiently scan and validate a range of numbers, minimizing the risk of errors. So, let’s get started!

Find Armstrong Number Between Two Intervals in Python

Code

# Python program for armstrong number between two intervals 

def is_armstrong_number(number):
    num_str = str(number)
    num_digits = len(num_str)
    sum_of_digits = sum(int(digit) ** num_digits for digit in num_str)
    if sum_of_digits == number:
        return True
    else:
        return False

# Example usage
start = int(input("Enter the starting number: "))
end = int(input("Enter the ending number: "))

print(f"Armstrong numbers between {start} and {end}:")
for number in range(start, end + 1):
    if is_armstrong_number(number):
        print(number)

Output

Enter the starting number: 100
Enter the ending number: 500
Armstrong numbers between 100 and 500:
153
370
371
407

Explanation

  • We define the function is_armstrong_number to check whether a number is an Armstrong number or not, just like in our tutorial on Python program to find armstrong number or not.

  • In the example section, we prompt the user to enter the starting and ending numbers for the desired interval to search for Armstrong numbers. We then iterate over each number within that interval using a for loop.

  • For each number, we call the is_armstrong_number function to determine if it is an Armstrong number. If it is, we print the number.

Python Course

Find Armstrong Numbers Between 1 to 10000 in Python

Code

# Python program to print all Armstrong numbers between 1 and 10,000

def is_armstrong_number(number):
    num_str = str(number)
    num_digits = len(num_str)
    sum_of_digits = sum(int(digit) ** num_digits for digit in num_str)
    if sum_of_digits == number:
        return True
    else:
        return False

print("Armstrong numbers between 1 and 10,000:")
for number in range(1, 10001):
    if is_armstrong_number(number):
        print(number)

Output

Armstrong numbers between 1 and 10,000:
1
2
3
45
6
7
8
9
153
370
371
407
1634
8208
9474

Explanation

  • In this program, we have the is_armstrong_number function which checks whether a number is an Armstrong number or not.

  • We use a for loop to iterate over each number in the range from 1 to 10,000. For each number, we call the is_armstrong_number function to determine if it is an Armstrong number. If it is, we print the number.

Armstrong Number in Python Using for loop

Code

# Armstrong numbers between two intervals in Python using for loop

def is_armstrong_number(number):
    num_str = str(number)
    num_digits = len(num_str)
    sum_of_digits = sum(int(digit) ** num_digits for digit in num_str)
    if sum_of_digits == number:
        return True
    else:
        return False

# Example usage
start = int(input("Enter the starting number: "))
end = int(input("Enter the ending number: "))

print(f"Armstrong numbers between {start} and {end}:")
for number in range(start, end + 1):
    if is_armstrong_number(number):
        print(number)

Output

Enter the starting number: 1
Enter the ending number: 100
Armstrong numbers between 1 and 100:
1
2
3
4
5
6
7
8
9

Explanation

  • In this program, we reuse the is_armstrong_number function from the previous example to check whether a number is an Armstrong number or not.

  • In the example, we prompt the user to enter the starting and ending numbers for the range of values to check. Then, we iterate over each number within that range using a for loop.

  • For each number, we call the is_armstrong_number function to determine if it is an Armstrong number. If it is, we print the number.

  • By running this program, it will find and display all Armstrong numbers within the specified range using a for loop.

Armstrong Number in Python Using while loop

Code

# Armstrong numbers between two intervals in python using while loop

def is_armstrong_number(number):
    num_str = str(number)
    num_digits = len(num_str)
    sum_of_digits = sum(int(digit) ** num_digits for digit in num_str)
    if sum_of_digits == number:
        return True
    else:
        return False

# Example usage
start = int(input("Enter the starting number: "))
end = int(input("Enter the ending number: "))

print(f"Armstrong numbers between {start} and {end}:")
number = start

while number <= end:
    if is_armstrong_number(number):
        print(number)
    number += 1

Output

Enter the starting number: 100
Enter the ending number: 999
Armstrong numbers between 100 and 999:
153
370
371
407

Explanation

  • In this program, we use the is_armstrong_number function from the previous examples to check whether a number is an Armstrong number or not.

  • In the example, we prompt the user to enter the starting and ending numbers for the range of values to check. We initialize the variable number with the starting value.

  • Using a while loop, we continuously iterate as long as the number is less than or equal to the ending value. Within each iteration, we check if the current number is an Armstrong number using the is_armstrong_number function. If it is, we print the number.

  • After each iteration, we increment the number by 1 to move to the next number in the range.

By running this program, it will find and display all Armstrong numbers within the specified range using a while loop.

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Python Program to Find Armstrong Number in an Interval: Video